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from the top of a building the angles of depression of the top of the base of a lamppost, located a distanse away were measured and found to be 58 degrees and 75 degrees,respectively if the building is 90 feet high.Find the height of the lamp post
if sin(theta)=(a*a-b*b)/(a*a+b*b) find cos (theta) and tan(theta).
prove that sin(A)-sin(B)/cos(A)+cos(B) + cos(A)-cos(B)/sin(A)+sin(B)=0
2sin thetatan theta(1-tan theta0 + 2sin theta sec^2 theta
____________________________________________ =
(1-tan theta)^2
if(1+i) (1+2i) (1+3i)..........(1+ni)= x+iy
p/t 2.5.10.........〖1+n〗^2=x^2 〖+y〗^2
Fin the general solution of
3〖Cos〗^2 θ-√3 SinθCosθ-3〖Sin〗^2 θ=0
Solve the following equation
Sin2θ+Sin4θ+Sin6θ=0
Find the general solution of
tanθ+Cosθ=0
2tanα=3tanβ,P/t (tanα-β)=Sin2β/(5-Cos2β)
〖Cos〗^2 A+〖Cos〗^2 (A+2π/3) + 〖Cos〗^2 (A-2π/3)=3/2
Sinx/Cos3x+Sin3x/Cos9x+Sin9x/Cos27x=1/2(tan27x-tanx)
√3Cosec20°-Sec20°=4
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