Answer to Question #12176 in Trigonometry for sathya krishna sai

Question

prove that sin(A)-sin(B)/cos(A)+cos(B) + cos(A)-cos(B)/sin(A)+sin(B)=0

Answer 1

[sin(A)-sin(B)]/[cos(A)+cos(B)] +
[cos(A)-cos(B)]/[sin(A)+sin(B)]=
=[sin^2(A)-sin^2(B)+
cos^2(A)-cos^2(B)]/[(sin(A)+sin(B))(cos(A)+cos(B))] =
=(1-1)/
[(sin(A)+sin(B))(cos(A)+cos(B))] =0