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Prove that: sin4A-cos4A=sin2A-cos2A
A triangular piece of land is bounded by three straight roads, two of which intersect in a right angle. The third road makes an angle of 37.6° with one of the others. The perimeter of the land is 985 yards. What is its area, to the nearest square foot?
Given that cos a 12/3 and a is an angle in Quadrant II and that sin Beta = 3/5 is an angle in Quadrant I. Determine

a) cos (a + Beta)

b) sin (Beta - a)
Simplify:
2x^2y^4*4x^2y^4*3x
------------------------
3x^-3y^-2
Simplify:
9n^3)^3 *2n^-1
simplify:
(x^4)^-3 * 2x^4
sin(B-C/2)=(B-C)/a *cos(A/2)
find the value of A .if i.(cosec 2A-2)(cot 3A-1)=0 ii.cos 3A(2sin2A-1)=0
I forget how to factor. Can you please help:
3(x+4)^2=8
prove that sec^4a(1-sin^4a) - 2tan^2a = 1
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