Answer to Question #14627 in Trigonometry for Danielle

Question

Simplify:
2x^2y^4*4x^2y^4*3x
------------------------
3x^-3y^-2

Answer 1

2x^2y^4 * 4x^2y^4 * 3x
---------------------------- =
3x^-3y^-2

2 * x^2y^4 * 4 * x^2y^4 * 3 * x
= ------------------------------------ =
3 * x^-3y^-2

8 * x^2y^4 * x^2y^4 * x
= --------------------------- =
x^-3y^-2

8 * x^(4y^4 + 1)
= ------------------- = 8 * x^(4y^4 + 3y^2 + 1)
x^-3y^-2