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Prove: 1-(sec^6a+cos^6a)=3sin^2acos^2a
find the length of the arc subtended by a central angle of 352 degrees of a circle of radius 3 inches. give your answer to the nearest hundredth of an inch.
2cosA-sinA=x and cosA-sinA=y. Prove that 2x*x+y*y-2xy=5
Two vectors having equal magnitudes A make an angle θ with each other.The magnitude and direction of resultant are respectively:

a) 2Acos θ/2, along bisector
b) Acos θ/2, at 45 degree from one vector
c) Acos θ/2, along bisector

d)Asin θ/2, along bisector
If sin(x)=(1/11) (in quadrant 1)& find sin(2x)=
If cosecA=2,& & find the value of& 1/tanA + sinA/(1+cosA)
How do you find a second side of a triangle with using one side and two angles ?
Prove the following:
1) (1-sin^2 Q) sec^2 Q=1
2) cos^2Q (1+tan^2Q)=1
3) cos^2Q + 1/1+cot^2 Q=1
4) 1/1+sinQ + 1/1-sinQ=2sec^2Q
If F(x) = x² + 2 and G(x) = 2/x, find (G ○ F)(2)
Solve the trigonometric equation:-

3cos^2x - 2 root 3 sinx cosx - 3sin^2x = 0
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