Question

tan(beta)+sin(beta)sec(beta)-sin(beta)cos(beta)/sec(beta)-csc(beta)=tan(beta)+sin(beta)sec(beta)

Answer 1

$$\tan \beta + \sin \beta \sec \beta - \frac {\sin \beta \cos \beta}{\sec \beta} - \csc \beta = \tan \beta + \sin \beta \sec \beta$$ $$\frac {\sin \beta}{\cos \beta} + \frac {\sin \beta}{\cos \beta} - \sin \beta \cos \beta \cos \beta - \frac {1}{\sin \beta} = \frac {\sin \beta}{\cos \beta} + \frac {\sin \beta}{\cos \beta}$$ $$2 \frac {\sin \beta}{\cos \beta} - \sin \beta \cos \beta \cos \beta - \frac {1}{\sin \beta} = 2 \frac {\sin \beta}{\cos \beta}$$ $$- \sin \beta \cos \beta \cos \beta - \frac {1}{\sin \beta} = 0$$

This identity is incorrect!