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At what point the graph of f(x) = 2cos x – 1 intersects the x-axis?
Hi. This is the question:
A jet flew 140 mi on a course of 196 degrees and then 120 mi on a course of 106 degrees then the jet return to its starting point via the shortest route possible. Find the total distance that the jet traveled.
I found the answer for this. It's this one:
http://ph.answers.yahoo.com/question/index?qid=20110828043233AAVgQcy
Now I understand everything else, ut my problem is why they used the given angles to confirm that it is a right triangle? I know this has something to do with theorems on parallel lines, but I just can't to picture how. Illustrations are greatly appreciated. (It will actually be a lot easier for me to understand this question). Thank you.
Let sin x = .93 and cos y = .29. Which is x + y?
If cot 33 = 1.54, which is tan 57?

A. 1.54
B. -1.55
C. 1.45
D. -1.50
If tan 54 = 1.38, which is tan 234?

A. -1.38
B. 1.38
C. -2.76
D. 2.76
If cos 88 = .03, which is sin 178?

A. .03
B. -.03
C. .97
D. -.97
Let sin 25 = .42. Which is sin 155?

A. -.42
B. .42
C. -8.2
D. .14
Let cos45=squareroot of 2 / 2. Which is cos135?

A. -squareroot of 2 / 3
B. squareroot of 2 / 2
C. squareroot of 2 / 3
D. -squareroot of 2 / 2
if cot30=squareroot of 3 which is cot 330?

A. - squareroot of 3
B. square root of 3
C. 2 square root of 3
D. -2 square root of 3
Let sin x = .16. Then:

A. x = cos^(–1) .16
B. x = cos^(–1) .99
C. x = sin .99
D. x = –sin .16
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