Question

Use the Law of Sines to find the length of side b in the following triangle.
Hint: (sin(A)/a)=(sin(B)/b)
B
c a

A C
b

If m<A = 47 degrees
m<B = 53 degrees
Length of side a = 7 feet

Answer 1

Use the Law of Sines to find the length of side $b$ in the triangle if angle $A = 47$ degrees angle $B = 53$ degrees and length of side $a = 7$ feet.

Solution:

According to the law of sines we can write next ratio:

$$\frac{a}{\sin(A)} = \frac{b}{\sin(B)}$$

Solving for $b$

$$b = \frac{\sin(B)}{\sin(A)} * a$$

Substitute our values:

$$b = \frac{\sin(53{}^\circ)}{\sin(47{}^\circ)} * 7 = \frac{0.799}{0.731} * 7 = 7.651$$

Answer: $b = 7.651$