Question #93300
Two ships P and Q left a port R at the same time on different routes. Q sailed on a bearing of 150° while P sailed on the north side of Q.After a distance of 8km and 10 km by p anq respectively their distance apart was 12km. Find the bearing of P from R.
1
Expert's answer
2019-08-26T09:17:40-0400

Find the angle xx between RP and RQ using the law of cosines:


PQ2=RP2+RQ22RPRQcosxPQ^2=RP^2+RQ^2-2RP\cdot RQ\cdot cos xcosx=RP2+RQ2PQ22RPRQcos x=\frac{RP^2+RQ^2-PQ^2}{2RP\cdot RQ}cosx=82+1021222810=64+100144160=20160=18cos x=\frac{8^2+10^2-12^2}{2\cdot 8\cdot 10}=\frac{64+100-144}{160}=\frac{20}{160}=\frac{1}{8}

x83°x\approx 83\degree

Then the  bearing of P from R is:


150°83°=67°150\degree-83\degree=67\degree


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS