Question #77611

A mountain is seen in a direction 30° north of east and is known to be 5 miles away from another mountain as seen in a direction 40° north of east 8 mile distance. how far apart are the two?

Expert's answer

Answer on Question #77611 – Math – Trigonometry

Question

A mountain is seen in a direction 30∘30{}^{\circ} north of east and is known to be 5 miles away from another mountain as seen in a direction 40∘40{}^{\circ} north of east 8 mile distance. how far apart are the two?

Solution

cos⁡30∘=32=x5;x=2.53\cos 30{}^{\circ} = \frac{\sqrt{3}}{2} = \frac{x}{5}; \quad x = 2.5\sqrt{3}sin⁡30∘=12=k5;k=2.5\sin 30{}^{\circ} = \frac{1}{2} = \frac{k}{5}; \quad k = 2.5cos⁡40∘=0.77=z8;z=6.16\cos 40{}^{\circ} = 0.77 = \frac{z}{8}; \quad z = 6.16sin⁡40∘=0.64=v8;v=5.12\sin 40{}^{\circ} = 0.64 = \frac{v}{8}; \quad v = 5.12z−x=y;y=1.83z - x = y; \quad y = 1.83v−k=f;f=2.62v - k = f; \quad f = 2.62r=M1M2=y2+f2=3.2 milesr = M1M2 = \sqrt{y^2 + f^2} = 3.2 \text{ miles}


**Answer**: r=3.2r = 3.2 miles

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