Question #75489

(1) Using an identity from this section, write sin 7x − sin 3x as a product.
(2) Using an identity from this section, find the exact value of sin 105◦
sin 15◦
(3) Using an identity from this section, find the exact value of sin 195◦
cos 75◦
(4) Using identities from this section, verify the identity cos t−cos 3t over sin t+sin 3t = tan t.
(5) Using an identity from this section, write sin 7x sin 3x as a sum or a difference.

Expert's answer

Answer on Question # 75489 – Math – Trigonometry

Question

(1) Using an identity from this section, write sin7xsin3x\sin 7x - \sin 3x as a product.

(2) Using an identity from this section, find the exact value of sin105sin15\sin 105{}^\circ \sin 15{}^\circ

(3) Using an identity from this section, find the exact value of sin195cos75\sin 195{}^\circ \cos 75{}^\circ

(4) Using identities from this section, verify the identity costcos3t\cos t - \cos 3t over sint+sin3t=tant\sin t + \sin 3t = \tan t.

(5) Using an identity from this section, write sin7xsin3x\sin 7x \sin 3x as a sum or a difference.

Solution

1. sin7xsin3x=2cos5xsin2x\sin 7x - \sin 3x = 2 \cos 5x \sin 2x

2. sin105sin15=12[cos90cos120]=12x(12)=14\sin 105{}^\circ \sin 15{}^\circ = \frac{1}{2} [\cos 90{}^\circ - \cos 120{}^\circ] = \frac{1}{2} x \left(-\frac{1}{2}\right) = -\frac{1}{4}

3. sin195cos75=12[sin270+sin120]=12[1+32]=2+34\sin 195{}^\circ \cos 75{}^\circ = \frac{1}{2} [\sin 270{}^\circ + \sin 120{}^\circ] = \frac{1}{2} [-1 + \frac{\sqrt{3}}{2}] = \frac{-2 + \sqrt{3}}{4}

4. costcos3tsint+sin3t=2sin2tsint2sin2tcost=sintcost=tant\frac{\cos t - \cos 3t}{\sin t + \sin 3t} = \frac{2 \sin 2t \sin t}{2 \sin 2t \cos t} = \frac{\sin t}{\cos t} = \tan t

5. sin7xsin3x=12[cos4xcos10x]\sin 7x \sin 3x = \frac{1}{2} [\cos 4x - \cos 10x]

Answer: 1. Product form of sin7xsin3x\sin 7x - \sin 3x is 2cos5xsin2x2 \cos 5x \sin 2x

2. Exact value of sin105sin15\sin 105{}^\circ \sin 15{}^\circ is 14-\frac{1}{4}

3. Exact value of sin195cos75\sin 195{}^\circ \cos 75{}^\circ is 2+34\frac{-2 + \sqrt{3}}{4}

4. costcos3tsint+sin3t=tant\frac{\cos t - \cos 3t}{\sin t + \sin 3t} = \tan t (verified).

5. Expression of sin7xsin3x\sin 7x \sin 3x as a difference is 12[cos4xcos10x]\frac{1}{2} [\cos 4x - \cos 10x]

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