Question #58929

Just the answer please.
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Expert's answer

Answer on Question #58929 – Math – Trigonometry

Question

Which equation can be used to model simple harmonic motion?


d=acos(ωt)d = a \cos(\omega t)d=asin(ωt)+kd = a \sin(\omega t) + kd=acos[ω(t+k)]d = a \cos[\omega (t + k)]d=sin(aωt)d = \sin(a \omega t)


**Answer:** d=Acos(ωt)d = A \cos(\omega t).

Question

For the simple harmonic motion equation d=5sin(π4t)d = 5 \sin \left( \frac{\pi}{4} t \right), what is the maximum displacement from the equilibrium position? _____

Solution

For the simple harmonic motion equation d=5sin(π4t)d = 5 \sin \left( \frac{\pi}{4} * t \right), the amplitude is A=5A = 5, so the maximum displacement from the equilibrium position is 5.

**Answer:** 5.

Question

For the simple harmonic motion equation d=5sin(π4t)d = 5 \sin \left( \frac{\pi}{4} t \right), what is the period? _____

Solution

d=5sin(π4t),T=2πw,w=π4.d = 5 \sin \left( \frac{\pi}{4} * t \right), \quad T = \frac{2\pi}{w}, \quad w = \frac{\pi}{4}.Period is T=2ππ4=8 s.\text{Period is } T = \frac{2\pi}{\frac{\pi}{4}} = 8 \text{ s}.


**Answer:** 8 s.

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