Question #273747

A= 82°, b=100°, c=78° Find: B

1
Expert's answer
2021-12-01T11:25:39-0500

Solution;

From the law of Sine and cosine;

sinasinB=sinbsinB=sincsinC+...\frac{sina}{sinB}=\frac{sinb}{sinB}=\frac{sinc}{sinC}+...

Also;

Cosa=cos(b)cos(c)+sin(b)sin(c)(cosA)Cosa=cos(b)cos (c)+sin(b)sin(c)(cos A)

By direct substitution;

Cos(a)=cos100cos78+sin(100)sin(78)cos(82)Cos (a)=cos100cos78+sin(100)sin(78)cos(82)

Cos(a)=0.09796

Hence;

a=84.38°a=84.38°

Now;

Sin(B)=sin(b)sin(A)sin(a)Sin(B)=\frac{sin(b)sin(A)}{sin(a)}

Sin(B)=sin(100)sin(82)sin(84.38Sin(B)=\frac{sin(100)sin(82)}{sin(84.38}

Sin(B)=0.9799Sin(B)=0.9799

B=78.5°



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