By drawing a relevant triangle,prove that
tan θ = sin θ / cos θ
and
cos^2 θ + sin^2 θ = 1
Consider the right-angled triangle ABC, with AB=1, C = 90° and A= θ°.
"\\sin \\theta =\\frac{BC}{AB}=\\frac{BC}{1}=BC"
"\\cos \\theta =\\frac{AC}{AB}=\\frac{AC}{1}=AC"
"\\tan \\theta =\\frac{BC}{AC}=\\frac{\\sin \\theta}{\\cos \\theta}"
Pythagorean theorem: "1=AC^2+BC^2=\\cos ^2\\theta +\\sin^2\\theta"
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