Let "x" mts be the height to the tip of the CN tower from the clinometer. Then "(x + 1.5)m" is the height of the CN tower from the base. (Refer above figure.). Given, Ross stands 750m from the base and sights the tip of the tower at an angle "36^{\\circ}". Then, from the figure we get
"\\tan 36^{\\circ} = \\dfrac{x}{750}\\\\\nx=750*0.73 = 547.5~~~(\\tan(36^{\\circ}) \\approx 0.73)."
Therefore, height of the CN tower from the base "\\approx 547.5+1.5=549m."
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