We are given:
One side of a rectangle is 9 cm.
Another side of the rectangle is also given which is 19 cm. But, we will not take this value to calculate the area of the rectangle because this side is changing.
So, we will assume that another side will be x cm.
Increasing rate of another side is:
dtdx=5 cm./min.
Now:
We know that, the area of this rectangle is:
A=9x (Equation 1)
Derivative of (Equation 1) with respect to t is:
dtd(A)=dtd(9x)
⇒dtdA=9dtd(x)+xdtd(9) [∵dxd(f(x)g(x))=f(x)dxd(g(x))+g(x)dxd(f(x))]
⇒dtdA=9dtdx+x(0) [∵dxd(c)=0(Where c is a constant)]
⇒dtdA=9(5)[∵dtdx=5]
⇒dtdA=45
Hence:
The area of the rectangle is changing at the rate of 45 square centimeters per minute.
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