As we know that earth is completing one round around the sun in "365\\dfrac{1}{4}" days on average.
The longest day is June 21, on this day sun rise at 4:47AM and sunset at 7:38PM, so the daylight hour is 14hour 51 min. So daylight hour is 14.85hour.
And on the shortest day is December 21, on this day sun rise at 7:24AM and sunset at 4:54PM, so the daylight hour is 9.48 daylight.
So the amplitude of the daylight hour = "\\dfrac{14.85-9.48}{2}=2.685" hours
mid line of the ="\\dfrac{14.85+9.48}{2}=12.165hours"
The average time period of the cosine function ="365"
So, the cosine function without the horizontal shift "f(x)=2.685\\sin(\\dfrac{2\\pi}{365}t)+12.175"
So, if we are taking any random day for example Jan 14,
It is the 207th day after the longest day.
So, "f(207)=2.685\\sin(\\dfrac{2\\pi}{365}207)+12.175=9.734hours"
Which is reasonable as compared to 21Dec, from the shortest day, which is just 3 weeks near to the shortest day.
Comments
Thank you so much! I was given a data set of the daylight hours of a couple of cities (Tokyo,Yakutsk and Adelaide). Thanks to this article, I did not need to plot the graphs on Desmos to calculate the amplitude. I also have a question. How does the amplitude vary with the geographical location of the cities? What is the relation? Thank you once again!
Leave a comment