Let the position vector of a stone at time,t be given as r(t)=cosh (t^2-1)I+ sinh(1-t)j+Bt^2k
Assume that the position vector is Normal to the acceleration vector.
Find the value of B at Time t=5seconds
t=5t=5t=5
There are no solution for B∈R.B\in \R.B∈R.
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