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Fifteen trainees in a technical program are randomly assigned to three different types of
instructional approaches, all of which are concerned with developing a specified level of skill
in computer-assisted design. The achievement test scores at the conclusion of the
instructional unit are reported in Table along with the mean performance score associated
with each instructional approach. Use the analysis of variance procedure to test the null
hypothesis that the three-sample means were obtained from the same population, using the
5 percent level of significance for the test.
on an average a box containing 10 articles is likely to have 2 defectives. if we consider the consignment of 100 boxes, how many of them are expected to three or less defectives ?
A banana has a mean weight of 120 grams with a standard deviation of 3 grams. How many standard deviations below the mean is a banana that is 111 grams?

Assume that the total score (from both teams) for college football games averages µ = 42 points per game, and that the distribution of total points is approximately normal with σ = 20. What is the likelihood of 4 randomly selected games having an average point total of over 60 points?


In testing the independence of two variable described in conducted table, the critical value of a chi-square if the rest is to be conducted at the level of significance a= 0.05 and the degrees of the freedom df=5 is
1. 0.412
2. 9.236
3. 16. 756
4. 15.086
5. 11.071
For each of the following pairs of null hypothesis (H0) and an alternative (H1)
A. H0 u=10 against H1 u-30
B. H0 u=30 against H1 u-30
C. H0 x=15 against H1 u-15
D. H0 u=75 against H1 u-75
Which pair is deemed in appropriate
1. Only C Because of sample mean
2. B and D Because of two -tail test
3. A and C Because of one- tail test
4. A, B and C Because of unordered value of u
5. Only Because of the largest value of u
For a simple random sample of 15 items from a population that is approximately normally distributed with a sample mean X =82 and a sample standard deviation S=20.5. The 95% confidence interval of the population mean is
1. 70.6463 ; 93.3537
2. 721.6789 ; 91,3211
3. 71.6256 ; 92.3744
4. 70.7204 ; 93.2796
5. 70.6463 ;93.3537
When constructning a confidence interval, the t-distribution is used when
1. The sample size is provided
2. The population variance is given
3. The sample variance is given
4. The question is to calculate the 95% confidence interval of the mean
5. The level of significance is 1%, 5%, 10%
Suppose that a random sample of size n=100 is selected from a binomial population proportion with the population proportion 0.25
The calculated standard error equal to
1. 0.0019
2. 0.0433
3. 0.0025
4. 0.0001
5. 25
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