Question #141106

A banana has a mean weight of 120 grams with a standard deviation of 3 grams. How many standard deviations below the mean is a banana that is 111 grams?

Expert's answer

Z=XμσZ=\frac{X-\mu}{\sigma}

=1111203=3=\frac{111-120}{3}=-3

A banana that is 111 is 3 standard deviations below the mean.


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