Possibility spaceS: the class of 20 children.
a) Event A: member of the athletics team is chosen
P(A)=204+3=207=0.35 b) Event B: female is chosen
P(B)=2011=0.55 c) Event: a female member of the athletics team P(A∩B).
There are 3 girls in the athletics team. Then
P(A∩B)=203=0.15 d) Event: a female or in the athletics team P(A∪B)
P(A∪B)=P(A)+P(B)−P(A∩B)=
=207+2011−203=43=0.75
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