Answer to Question #86837 in Statistics and Probability for Anand

Question #86837
If a random variable X₁ has mean 4 and variance 9, while the random variable X₂
has mean − 2and variance 5, and the two are independent, find
i) E(2X₁ + X₂ - 5)
ii) Var(2X₁ + X₂ - 5)
1
Expert's answer
2019-03-27T06:29:53-0400
E(X1)=4,Var(X1)=9,E(X2)=2,Var(X2)=5.E(X_1)=4, Var(X_1)=9, E(X_2)=-2, Var(X_2)=5.

i)E(2X1+X25)=2E(X1)+E(X2)5=2425=1i) E(2X_1+X_2-5)=2E(X_1)+E(X_2)-5=2*4-2-5=1



ii) If X1 and X2 are independent then



Var(2X1+X25)=22Var(X1)+Var(X2)=49+5=41Var(2X_1+X_2-5)=2^2Var(X_1)+Var(X_2)=4*9+5=41


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Comments

Assignment Expert
10.05.21, 11:39

Dear Hi, please use the panel for submitting a new question.

Hi
09.05.21, 14:11

Consider a standard normal distributed random variable Z with Za= 0.9. It means P(Z > 0.9) = a True Faise

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