Question #86790

Assume that females have pulse rates that are normally distributed with a mean of mu equals 76.0
beats per minute and a standard deviation of sigma equals 12.5
beats per minute. . If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 79 beats per minute.
The probability is ...

Expert's answer

We are given that females have pulse rates that are normally distributed with a


μ=76,σ=12.5.\mu=76, \sigma=12.5.z=xμσ/nz={{\overline{x}-\mu} \over {\sigma / \sqrt{n}}}z=797612.5/1=0.24z={{79-76} \over {12.5 / \sqrt{1}}}=0.24

We have to find


P(x<79)=P(z<0.24)=0.5948.P(\overline{x}<79)=P(z<0.24)=0.5948.

The probability is


P(x<79)=0.5948P(\overline{x}<79)=0.5948


LATEST TUTORIALS
APPROVED BY CLIENTS