Since two regression lines always intersect at a point representing mean values of the values xmean and ymean
8x−10y+66=040x−18y−214=0
8x−10y=−66
32y=544=>ymean=17
xmean=(10∗17−66)/8=13
xmean=13,ymean=17
(ii) To find the given regression equations in such a way that the coefficient of dependent variable is less than one at least in one equation.
8x−10y=−66=>y=66/10+8x/10 byx = 0.8
40x−18y=214=>x=214/40+18y/40 bxy = 0.45
r=sqrt(bxy∗byx)
r=sqrt(0.45∗0.8)=0.6 Coefficient of correlation r between x and y is 0.6.
(iii) To determine the standard deviation of y , consider the formula:
σy=(σx∗byx)/r
σy=0.8∗sqrt(9)/0.6=4
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