Question #86253

In a partially destroyed laboratory, record of an analysis of correlation of data,
only the following results are legible:
Variance of X = 9
Regression equations are
(i) 8x −10y + 66 = 0
(ii) 0 40x −18y − 214 =
Find out the following missing results.
(i) The means of X and Y
(ii) The coefficient of correlation between x and y
(iii) The standard deviation of Y

Expert's answer

Since two regression lines always intersect at a point representing mean values of the values xmean and ymean


8x−10y+66=08x-10y+66=040x−18y−214=040x-18y-214=0

8x−10y=−668x-10y=-66

32y=544=>ymean=1732y=544 => ymean=17

xmean=(10∗17−66)/8=13xmean=(10*17-66)/8=13

xmean=13,ymean=17xmean=13, ymean=17

(ii) To find the given regression equations in such a way that the coefficient of dependent variable is less than one at least in one equation.


8x−10y=−66=>y=66/10+8x/108x-10y=-66 => y=66/10+8x/10

byx = 0.8


40x−18y=214=>x=214/40+18y/4040x-18y=214 => x=214/40+18y/40

bxy = 0.45


r=sqrt(bxy∗byx)r = sqrt ( bxy * byx )

r=sqrt(0.45∗0.8)=0.6r = sqrt(0.45 * 0.8)=0.6

Coefficient of correlation r between x and y is 0.6.

(iii) To determine the standard deviation of y , consider the formula:


σy=(σx∗byx)/r\sigma y = (\sigma x * byx)/r

σy=0.8∗sqrt(9)/0.6=4σy= 0.8 * sqrt(9) / 0.6 = 4


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