Question #84129

Consider a random sample (WOR) of two households from a population of households having monthly income (in Rs.) as follows:
Household 1 2 3 4 5
Income 1000 1200 900 1500 1300
Enumerate all possible samples (WOR) of size 2 and show that the sample mean gives an unbiased estimate of population mean.
1

Expert's answer

2019-02-26T09:27:08-0500

Answer to Question #84129 - Math - Statistics and Probability

Question: Consider a random sample (WOR) of two households from a population of households having monthly income (in Rs.) as follows:



Enumerate all possible samples (WOR) of size 2 and show that the sample mean gives an unbiased estimate of population mean.

Solution: The given population has total 5 households, and here we shall consider a random sample "without replacement". Therefore, there are total (52)=10\binom{5}{2} = 10 possible outcomes for a sample of size 2.

In the following table, we represent these 10 outcomes and compute sample mean for each case:



True mean of the population is,


μ=1000+1200+900+1500+13005=59005=1180\mu = \frac {1 0 0 0 + 1 2 0 0 + 9 0 0 + 1 5 0 0 + 1 3 0 0}{5} = \frac {5 9 0 0}{5} = 1 1 8 0


As each of the 10 possible outcomes for the sample of size 2 is equally likely, each of them will occur with probability 110\frac{1}{10}. Therefore, the expectation is sample mean is,


E(Xˉ)=110×(1100+950+1250+1150+1050+1350+1250+1200+1100+1400)=110×11800=1180=μ\begin{array}{l} E(\bar{X}) \\ = \frac{1}{10} \times (1100 + 950 + 1250 + 1150 + 1050 + 1350 + 1250 + 1200 + 1100 + 1400) \\ = \frac{1}{10} \times 11800 \\ = 1180 = \mu \end{array}


Hence, we have, E(Xˉ)=μE(\bar{X}) = \mu

This shows that, sample mean is unbiased estimate of population mean.

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