(3) The probability that a regularly scheduled flight departs on time is P(D) = 0.83;the probability that it arrives on time is P(A) = 0.82; and the probability that it departs and arrives on time is P(D ∩A) = 0.78. Find the probability that a plane(a) arrives on time, given that it departed on time, and (b) departed on time, given that it has arrived on time.
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Dear iftikhar Ahmad, the answer will be P(not(A)|D)=1-P(A|D)=1-(0.78/0.83)=0.05/0.83=5/83.
I want to know that what will be the answer when we change it like this (a) arrives late, given that it departed on time
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Thanks a lot. Still awaiting the answer
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