The breaking strengths of cables produced by manufacturer have a mean of 1800 Kg and a standard deviation of 100 Kg. by a new technique in the manufacturing process, it is claimed that breaking strength can be increased. To test this claim, a sample of 50 cables is tested and it is found that the mean breaking strength is 1850Kg. can we support the claim at the 0.01 significance level?
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ruchita
30.11.19, 12:34
A company has 500 cables . A test of 40 cables selected at random
showed a mean breaking strength of 2400 pounds(lb) and a standard
deviation of 150 lb. What are the 95% and 99% confidence limits for
estimating the mean breaking strength of the remaining 460 cables.
Assignment Expert
05.07.18, 18:22
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ANGELA OUMA
05.07.18, 17:49
What is meant by a p- value? (b) State whether the null hypothesis
should be rejected on the basis of the given P- value (i) P-value =
0.258, α = 0.05, one tailed test (ii) P-value = 0.0684, α = 0.10,
two tailed test (iii)P-value = 0.0153, α = 0.01, one tailed test (iv)
P-value = 0.0232, α = 0.05, two tailed test (v) P-value = 0.002, α =
0.01, one tailed test.
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Dear visitor, please use the panel for submitting new questions.
A company has 500 cables . A test of 40 cables selected at random showed a mean breaking strength of 2400 pounds(lb) and a standard deviation of 150 lb. What are the 95% and 99% confidence limits for estimating the mean breaking strength of the remaining 460 cables.
Dear visitor, please use the panel for submitting new questions.
What is meant by a p- value? (b) State whether the null hypothesis should be rejected on the basis of the given P- value (i) P-value = 0.258, α = 0.05, one tailed test (ii) P-value = 0.0684, α = 0.10, two tailed test (iii)P-value = 0.0153, α = 0.01, one tailed test (iv) P-value = 0.0232, α = 0.05, two tailed test (v) P-value = 0.002, α = 0.01, one tailed test.
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