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Answer to Question #60646 in Statistics and Probability for koel
Question #60646
a) If 6n tickets numbered 1 ,1,0 ,2 K, 6n − are placed in a bag and three are drawn out,
show that the probability that the sum of the numbers on them is equal to 6n is
3n /(6n − 6()1 n − )2 . (5)
b) From a bag containing 3 white and 5 black balls, 4 balls are transferred into an empty
vessel. From this vessel a ball is drawn and is found to be white. What is the
probability that out of four balls transferred 3 are white and 1 is black?
show that the probability that the sum of the numbers on them is equal to 6n is
3n /(6n − 6()1 n − )2 . (5)
b) From a bag containing 3 white and 5 black balls, 4 balls are transferred into an empty
vessel. From this vessel a ball is drawn and is found to be white. What is the
probability that out of four balls transferred 3 are white and 1 is black?
Expert's answer
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Comments
If the tickets are not greater than 3n-1, then there may be several variants to sum up three tickets to get 6n. An example is 3n-2, 3n-1, 3.
how think to draw three tickets sum of 6n in case of 3n-1
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