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Answer to Question #45194 in Statistics and Probability for Anchu
Question #45194
In a normal distribution 31% of the items are under 45 and 8% are over 64. Find the mean and standard deviation of the distribution
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The first z-value can be obtained from the equality P(Z< z1)=0.31. It is known from statistical tables that P(Z <-0.5)=0.30854, but it is closer to 0.31 than P(Z <-0.49)=0.31207. Thus, z1 is approximately equal to -0.5.The second z-value can be obtained from the equality P(Z < z2)=0.31+0.19+0.42=0.92. It is known from statistical tables that P(Z < 1.41)=0.92073, but it is closer to 0.92 than P(Z < 1.40)=0.91924. Thus, z2 is approximately equal to 1.41.
I am not able to understand 1.41
I am not able to access 0.5 & 1.41 values from statistical standard normal distribution table..
Dear TOLU, The expert has provided the following response to your question about "0.50": It is just one-half of area of cumulative probability graph (below the mean or above the mean). Total area =1.
Dear TOLU. Your question has infinitely many solutions. Notice that all observations are arranged in the ascending order. The sample size is seven, which is an odd number. The sample median is equal to the (n+1)/2=(7+1)/2=4th item term, that is, 5. If the mean equals the median 5, then (x+1+4+5+6+9+y)/7=5, hence x+25+y=35, x+y=10, where x>0, y
?,1,4,5,6,9,?. Figure out the missing values such that mean for this data equals median. assume x can take only positive values that is x>0
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