Question #39168

I have seen the demonstration of beta distribution in youtube (https://www.youtube.com/watch?v=3vBBh0SDpqM) at the last B(m,n) is calculated as: (n-1)!(m-1)!/(m+n-1)!.

The question that I ask is:

This last result is obtained for m and n as integers ? if these last ones are réel, what will us obtained for the beta distribution.

I suppose that it will gamma distribution but i'm not sur.

Expert's answer

Answer on Question #39168 - Math – Statistics

Question: I have seen the demonstration of beta distribution in youtube (https://www.youtube.com/watch?v=3vBBh0SDpqM) at the last B(m,n) is calculated as: (n-1)!(m-1)!/(m+n-1)!.

The question that I ask is:

This last result is obtained for m and n as integers ? if these last ones are réel, what will us obtained for the beta distribution. I suppose that it will gamma distribution but i'm not sure.

Answer: B(m,n)=(n−1)!(m−1)!(m+n−1)!B(m,n) = \frac{(n - 1)!(m - 1)!}{(m + n - 1)!} only for positive integers.

In general, for positive real numbers xx and yy,


B(x,y)=Γ(x)Γ(y)Γ(x+y),B(x, y) = \frac{\Gamma(x) \Gamma(y)}{\Gamma(x + y)},


where Γ(x)\Gamma(x) is the gamma function.

You can read about it here:

http://en.wikipedia.org/wiki/Beta_function#Relationship_between_gamma_function_and_beta_function

For gamma function, we have that for natural n, Γ(n)=(n−1)!\Gamma(n) = (n - 1)!. So, substituting this into formula above, we obtain that B(m,n)=(n−1)!(m−1)!(m+n−1)!B(m,n) = \frac{(n - 1)!(m - 1)!}{(m + n - 1)!} (m and n are natural numbers).

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