Question #38879

Suppose it is estimated that a person visiting Florida will visit Disney World, Busch Gardens, or both with probabilities 0.5, 0.3, and 0.2, respectively. Find the probability that a person visiting Florida will visit Busch Gardens given that the person did visit Disney World. (Enter your probability as a fraction.)
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Expert's answer

2014-02-06T06:03:26-0500

Answer on Question 38879, Math, Statistics and Probability You will need Baye's theorem here


P(AB)=P(BA)P(A)P(B)P(A|B) = \frac{P(B|A) P(A)}{P(B)}


Here AA is visiting both Disney World and Busch Gardens, BB is visiting Disney World, P(BA)P(B|A) is probability to visit Disney World when both Disney World and Busch Gardens were visited and its obviously equal to 1. Hence we have


P(AB)=10.20.5=0.4=25P(A|B) = \frac{1 \cdot 0.2}{0.5} = 0.4 = \frac{2}{5}

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