Answer to Question #348087 in Statistics and Probability for Bianca

Question #348087

200 graduating students are selected and it is found that 114 will be awarded the first class honors degrees calculate the 95% confidence interval for the proportion of the graduating students who will receive first class honors degrees

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Expert's answer
2022-06-06T23:56:59-0400

The critical value for α=0.05\alpha = 0.05 is zc=z1α/2=1.96.z_c = z_{1-\alpha/2} = 1.96.

p^=XN=114200=0.57\hat{p}=\dfrac{X}{N}=\dfrac{114}{200}=0.57

The corresponding confidence interval is computed as shown below:


CI(Proportion)=(p^zc×p^(1p^)n,CI(Proportion)=(\hat{p}-z_c\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}},p^+zc×p^(1p^)n)\hat{p}+z_c\times \sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}})=(0.571.96×0.57(10.57)200,=(0.57-1.96\times \sqrt{\dfrac{0.57(1-0.57)}{200}},0.57+1.96×0.57(10.57)40)0.57+1.96\times \sqrt{\dfrac{0.57(1-0.57)}{40}})=(0.5014,0.6386)=(0.5014, 0.6386)

Therefore, based on the data provided, the 95% confidence interval for the population proportion is 0.5014<p<0.6386,0.5014 < p < 0.6386, which indicates that we are 95% confident that the true population proportion pp is contained by the interval (0.5014,0.6386).(0.5014, 0.6386).

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