Question #348045

A jar contains 9 red marbles numbered 1 to 9 and 8 blue marbles numbered 1 to 8. A marble is drawn at random from the jar. Find the probability that the marble is blue AND even-numbered.



Expert's answer

We know that

P(event)=number of favorable outcomesnumber of total outcomes.P(event)=\frac{number\: of\: favorable\: outcomes}{number\: of\: total\: outcomes}.


The total number of marbles is 9+8=17.9+8=17.

Among them we have 4 blue AND even-numbered marbles (numbered 2, 4, 6, 8).

So

P(getting blue AND even-numbered marble)=417.=\frac{4}{17}.


Answer: 417.\frac{4}{17}.


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