Question #344140

Suppose that the mean weight of school children’s bookbags is 17.41 pounds, with a standard deviation of 2.2 pounds. Find the probability that the mean weight of a sample of 30 bookbags will exceed 17 pounds.


1
Expert's answer
2022-05-24T10:23:12-0400

Set the weights of school children's book bags as variable x.

Given: xN(17.41,2.22)x\thicksim N(17.41,2.2^2)

n(x)=30n(x)=30

Get: μxˉ=μx=17.41,\mu_{\=x}=\mu_x=17.41, σxˉ2=σx2n=2.2230=(2.230)2\sigma_{\=x}^2=\frac{\sigma_x^2}{n}=\frac{2.2^2}{30}=(\frac{2.2}{\sqrt{30}})^2

xˉN(17.41,(2.230)2)\=x\thicksim N(17.41,(\frac{2.2}{\sqrt{30}})^2)

P(xˉ>17)=1P(xˉ17)=1P(xˉ17.412.2301717.412.230)=1P(z1.02)=1Z(1.02)=1[1Z(1.02)]=Z(1.02)=0.8461P(\=x>17)=1-P(\=x\le17)\\ =1-P(\frac{\=x -17.41}{\frac{2.2}{\sqrt{30}}}\le\frac {17-17.41}{\frac{2.2}{\sqrt{30}}})\\ =1-P(z\le-1.02)=1-Z(-1.02)\\ =1-[1-Z(1.02)]=Z(1.02)\\ =0.8461

(using z-score table)


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