Suppose that the mean weight of school children’s bookbags is 17.41 pounds, with a standard deviation of 2.2 pounds. Find the probability that the mean weight of a sample of 30 bookbags will exceed 17 pounds.
Set the weights of school children's book bags as variable x.
Given: "x\\thicksim N(17.41,2.2^2)"
"n(x)=30"
Get: "\\mu_{\\=x}=\\mu_x=17.41," "\\sigma_{\\=x}^2=\\frac{\\sigma_x^2}{n}=\\frac{2.2^2}{30}=(\\frac{2.2}{\\sqrt{30}})^2"
"\\=x\\thicksim N(17.41,(\\frac{2.2}{\\sqrt{30}})^2)"
"P(\\=x>17)=1-P(\\=x\\le17)\\\\\n=1-P(\\frac{\\=x -17.41}{\\frac{2.2}{\\sqrt{30}}}\\le\\frac {17-17.41}{\\frac{2.2}{\\sqrt{30}}})\\\\\n=1-P(z\\le-1.02)=1-Z(-1.02)\\\\\n=1-[1-Z(1.02)]=Z(1.02)\\\\\n=0.8461"
(using z-score table)
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