Question #343683

An oil company sends out monthly statements to its customers who purchased gasoline and other items using the company’s credit card. Until now, the company has not included a pre-addressed envelope for returning payments. The mean number of days before payment is received is 9.8. As an experiment to determine whether enclosing pre-addressed envelopes speeds up payment, 150 customers selected at random were sent pre-addressed envelopes with their bills. The sample statistics showed a mean of 9.16 days and a standard deviation of 2.642 days. Do the data provide sufficient evidence at 5% level of significance to establish that enclosure of pre-addressed envelopes improves the average speed of payments?


1
Expert's answer
2022-05-23T16:56:26-0400

The following null and alternative hypotheses need to be tested:

H0:μ9.8H_0:\mu\ge9.8

Ha:μ<9.8H_a:\mu<9.8

This corresponds to a left-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, df=n1=149df=n-1=149 degrees of freedom, and the critical value for a left-tailed test is tc=1.655145.t_c =-1.655145.The rejection region for this left-tailed test is R={t:t<1.655145}.R = \{t:t<-1.655145\}.

The t-statistic is computed as follows:



t=9.169.82.642/150=2.9668t=\dfrac{9.16-9.8}{2.642/\sqrt{150}}=-2.9668

Since it is observed that t=2.9668<1.655145=tc,t =-2.9668<-1.655145=t_c, it is then concluded that the null hypothesis is rejected.

Using the P-value approach:

The p-value for left-tailed df=149df=149 degrees of freedom, t=2.9668t=-2.9668 is p=0.001753,p= 0.001753, and since p=0.001753<0.05=α,p= 0.001753<0.05=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu is less than 9.8, at the α=0.05\alpha = 0.05 significance level.


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