Question #342560


(a) Identify the claim and state H0 and Ha.

(b) Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed, and whether to use a z-test, a t-test, or a chi-square test. Explain your reasoning.

(c) Choose one of the options. If convenient, use technology.

Option 1: Find the critical value(s), identify the rejection region(s), and find the appropriate standardized test statistic.

Option 2: Find the appropriate standardized test statistic and the P-value.

(d) Decide whether to reject or fail to reject the null hypothesis.

(e) Interpret the decision in the context of the original claim.


4. A research center claims that more than 55% of U.S. adults think that it is essential that the United States continue to be a world leader in space exploration. In a random sample of 25 U.S. adults, 64% think that it is essential that the United States continue to be a world leader in space exploration. At a = 0.05, is there enough evidence to support the center’s claim?


1
Expert's answer
2022-05-24T14:56:08-0400

(a) The following null and alternative hypotheses for the population proportion needs to be tested:

H0:p0.55H_0:p\le0.55

Ha:p>0.55H_a:p>0.55

(b) This corresponds to a right-tailed test, for which a z-test for one population proportion will be used.

(c) Based on the information provided, the significance level is α=0.05,\alpha = 0.05, and the critical value for a right-tailed test is zc=1.96.z_c = 1.96.

The rejection region for this right-tailed test is R={z:z>1.96}.R = \{z: z > 1.96\}.

The z-statistic is computed as follows:


z=p^pp(1p)n=0.640.550.55(10.55)25=0.9045z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}=\dfrac{0.64-0.55}{\sqrt{\dfrac{0.55(1-0.55)}{25}}}=0.9045

Since it is observed that z=0.9045<1.96=zc,z =0.9045< 1.96=z_c, it is then concluded that the null hypothesis is not rejected.

Using the P-value approach:

The p-value is p=P(Z>0.9045)=0.182865,p=P(Z>0.9045)=0.182865, and since p=0.182865>0.05=α,p =0.182865> 0.05=\alpha, it is concluded that the null hypothesis is not rejected.

Therefore, there is not enough evidence to claim that the population proportion pp is greater than 0.55, at the α=0.05\alpha = 0.05 significance level.


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