Answer to Question #342058 in Statistics and Probability for Revonia Letsoalo

Question

If P(E1)=P(E2)=0.15, P(E3)=0.4, and P(E4)=2P(E5), calculate the P (E4) and P(E5).

Answer 1

We know that total probability =1

i.e. sum of probabilities $P(E_1)+P(E_2)+P(E_3)+P(E_4)+P(E_5)=1$

So, $0.15+0.15+0.4+2x+x=1$

where $x=P(E_5)$

Solving for $x$ we get:

$3x=1-0.7$

$3x=0.3$

$x=0.1$

So, $P(E_5)=0.1$ and $P(E_4)=2*0.1=0.2$