Question #339765

Investigating a complaint from a buyer that there is short-weight selling, a manufacturer takes a random sample of twenty-five 32 g cans of coffee from a large shipment and finds that the mean weight is 31 g with a standard deviation of 0.6 g. Is there evidence of short-weighing at the 0.01 level significance?


1
Expert's answer
2022-05-11T17:51:10-0400

The following null and alternative hypotheses need to be tested:

H0:μ32H_0:\mu\ge32

Ha:μ<32H_a:\mu<32

This corresponds to a left-tailed test, for which a t-test for one mean, with unknown population standard deviation, using the sample standard deviation, will be used.

Based on the information provided, the significance level is α=0.01,\alpha = 0.01, df=n1=34df=n-1=34 degrees of freedom, and the critical value for a left-tailed test is tc=2.44115.t_c = -2.44115.

The rejection region for this left-tailed test is R={t:t<2.44115}.R = \{t: t<-2.44115\}.

The t-statistic is computed as follows:


t=xˉμs/n=31320.6/359.8601t=\dfrac{\bar{x}-\mu}{s/\sqrt{n}}=\dfrac{31-32}{0.6/\sqrt{35}}\approx-9.8601


Since it is observed that t=9.8601<2.44115=tc,t=-9.8601< -2.44115=t_c, it is then concluded that the null hypothesis is rejected.

Using the P-value approach:

The p-value for left-tailed, df=34df=34 degrees of freedom, t=9.8601t=-9.8601 is p=0,p=0, and since p=0<0.01=α,p=0<0.01=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu is less than 32, at the α=0.01\alpha = 0.01 significance level.


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