Answer to Question #338397 in Statistics and Probability for Developer

Question #338397

The probability that a car is stolen when it is parked overnight in an unsafe

area of a city is 10%. If there are 12 cars parked on a particular street of that

area, what is the probability that during a night

(i) no car is stolen?

(ii) at most two cars are stolen?

(iii) at least nine cars are stolen?


1
Expert's answer
2022-05-09T18:30:20-0400

Let X=X= the number of cars stolen:XBin(n,p).X\sim Bin(n, p).

Given n=12,p=0.1,q=1p=0.9.n=12, p=0.1, q=1-p=0.9.

(i)

P(X=0)=(120)(0.1)0(0.9)120P(X=0)=\dbinom{12}{0}(0.1)^0(0.9)^{12-0}

=0.28242953648=0.28242953648

(ii)


P(X2)=P(X=0)+P(X=1)+P(X=2)P(X\le2)=P(X=0)+P(X=1)+P(X=2)

=(120)(0.1)0(0.9)120+(121)(0.1)1(0.9)121=\dbinom{12}{0}(0.1)^0(0.9)^{12-0}+\dbinom{12}{1}(0.1)^1(0.9)^{12-1}

+(122)(0.1)2(0.9)122=0.88913002226+\dbinom{12}{2}(0.1)^2(0.9)^{12-2}=0.88913002226

(iii)


P(X9)=P(X=9)+P(X=10)P(X\ge9)=P(X=9)+P(X=10)

+P(X=11)+P(X=12)=(129)(0.1)9(0.9)129+P(X=11)+P(X=12)=\dbinom{12}{9}(0.1)^{9}(0.9)^{12-9}

+(1210)(0.1)10(0.9)1210+(1211)(0.1)11(0.9)1211+\dbinom{12}{10}(0.1)^{10}(0.9)^{12-10}+\dbinom{12}{11}(0.1)^{11}(0.9)^{12-11}

+(1212)(0.1)12(0.9)1212<0.000001+\dbinom{12}{12}(0.1)^{12}(0.9)^{12-12}< 0.000001


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