A psychologist has measured the IQ for a group of 30 children, now in the third grade, who had been regularly exposed to a new interactive, computerized teaching device. The mean IQ for these children is X = 106.
a. Test the null hypothesis that these children are no different from the general population of third-graders (μ = 100, σ = 6) using alpha = .05.
"H_0:a=100"
"H_1:a\\not=100"
Test statistic: "T={\\frac {(X-a)*\\sqrt{n}} {\\sigma}}={\\frac {(106-100)*\\sqrt{30}} 6}\\approx 5.48"
Since the population standard deviation is known, then it is appropriate to use z-score as critical value. So, "P(Z>Cr)={\\frac {\\alpha} 2}=0.025\\implies Cr=1.96"
Since "T\\notin (-Cr,Cr)=(-1.96,1.96)" , then we should conclude that, based on the given data, there is enough evidence to reject the null hypothesis and admit that average group IQ is different from population's
Comments
Leave a comment