Answer to Question #334058 in Statistics and Probability for Mikaela

Question

A population consists of values (1, 4, 7). Consider all possible samples of size n= 3 that can be drawn without replacement from this population.

a. Find the mean of the population.

b. Find the standard deviation of the population.

c. Find the mean of the sampling distribution of means.

d. Find the standard deviation of the sample distribution of means,

e.Construct the probability histogram of x with replacement

Answer 1

a. We have population values 1,4,7, population size N=3 and sample size n=3.

Mean of population $(\mu)$ = $\dfrac{1+4+7}{3}=4$

b. Variance of population 

$$\sigma^2=\dfrac{\Sigma(x_i-\bar{x})^2}{n}=\dfrac{1}{3}(9+0+9)=6$$

$$\sigma=\sqrt{\sigma^2}=\sqrt{6}\approx2.4495$$

c. The number of possible samples which can be drawn with replacement is $N^n=3^3=27$

$$\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} no & Sample & Sample \\ & & mean\ (\bar{x}) \\ \hline 1 &1,1,1 & 1\\ \hdashline 2 & 1,1,4 & 2 \\ \hdashline 3 & 1,1,7 & 3\\ \hdashline 4 & 1,4,1 & 2\\ \hdashline 5 & 1,4,4 & 3 \\ \hdashline 6 & 1,4,7& 4 \\ \hdashline 7 & 1,7,1 & 3 \\ \hdashline 8 & 1,7,4 & 4 \\ \hdashline 9 & 1,7,7 & 5 \\ \hdashline 10 & 4,1,1 & 2\\ \hdashline 11 & 4,1,4 & 3 \\ \hdashline 12 & 4,1,7 & 4 \\ \hdashline 13 & 4,4,1 & 3 \\ \hdashline 14 & 4,4,4 & 4 \\ \hdashline 15 & 4,4,7 & 5 \\ \hdashline 16 & 4,7,1 & 4 \\ \hdashline 17 & 4,7,4 & 5 \\ \hdashline 18 & 4,7,7 & 6\\ \hdashline 19 & 7,1,1 & 3\\ \hdashline 20 & 7,1,4 & 4\\ \hdashline 21 & 7,1,7 & 5\\ \hdashline 22 & 7,4,1 & 4\\ \hdashline 23 & 7,4,4 & 5\\ \hdashline 24 & 7,4,7 & 6\\ \hdashline 25 & 7,7,1 & 5\\ \hdashline 26 & 7,7,4 & 6\\ \hdashline 27 & 7,7,7 & 7\\ \hdashline \end{array}$$

$$\def\arraystretch{1.5} \begin{array}{c:c:c:c:c} \bar{X} & f(\bar{X}) &\bar{X} f(\bar{X}) & \bar{X}^2f(\bar{X}) \\ \hline 1 & 1/27 & 1/27 & 1/27 \\ \hdashline 2 & 3/27 & 6/27 & 12/27 \\ \hdashline 3 & 6/27 & 18/27 & 54/27 \\ \hdashline 4 & 7/27 & 28/27 & 112/27 \\ \hdashline 5 & 6/27 & 30/27 & 150/27 \\ \hdashline 6 & 3/27 & 18/27 & 108/27 \\ \hdashline 7 & 1/27 & 7/27 & 49/27 \\ \hdashline \end{array}$$

Mean of sampling distribution 

$$\mu_{\bar{X}}=E(\bar{X})=\sum\bar{X}_if(\bar{X}_i)=4=\mu$$

d. The variance of sampling distribution 

$$Var(\bar{X})=\sigma^2_{\bar{X}}=\sum\bar{X}_i^2f(\bar{X}_i)-\big[\sum\bar{X}_if(\bar{X}_i)\big]^2$$ $$=\dfrac{486}{27}-(4)^2=2= \dfrac{\sigma^2}{n}$$

$$\sigma_{\bar{X}}=\sqrt{2}\approx1.4142$$

e.