Question #333850



2. A researcher claims that the average salary of a private school teacher is greater than P20,000 with a standard deviation of P5,000. A sample of 20 teachers has a mean salary of P25,000. Test the claim of the researcher. At 0.05 level of significance, test the claim of the researcher.



Answer the following:



Parameter:


Claim:


Claim ( in symbol ):


Ho: Ho:


Ha: Ha:


What is the significance level or a?


Is it two-tailed or one-tailed test?

1
Expert's answer
2022-04-29T13:29:52-0400

Parameter: mean

Claim: the average salary of a private school teacher is greater than P20,000 

The following null and alternative hypotheses need to be tested:

H0:μ20000H_0:\mu\le20000

Ha:μ>20000H_a:\mu>20000

One-tailed test.

Significance level is α=0.05.\alpha = 0.05.

This corresponds to a right-tailed test, for which a z-test for one mean, with known population standard deviation will be used.

Based on the information provided, the significance level is α=0.05,\alpha = 0.05, and the critical value for a right-tailed test is zc=1.6449.z_c = 1.6449.

The rejection region for this right-tailed test is R={z:z>1.6449}.R = \{z: z > 1.6449\}.

The z-statistic is computed as follows:


z=xˉμσ/n=25000200005000/204.4721z=\dfrac{\bar{x}-\mu}{\sigma/\sqrt{n}}=\dfrac{25000-20000}{5000/\sqrt{20}}\approx4.4721

Since it is observed that z=4.4721>1.6449=zc,z = 4.4721>1.6449= z_c , it is then concluded that the null hypothesis is rejected.

Using the P-value approach: The p-value is p=P(Z>4.4721)=0,p=P(Z>4.4721)=0, and since p=0<0.05=α,p=0<0.05=\alpha, it is concluded that the null hypothesis is rejected.

Therefore, there is enough evidence to claim that the population mean μ\mu

is greater than 20000, at the α=0.05\alpha = 0.05 significance level.



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