We have a normal distribution, μ=164,σ=10.
Let's convert it to the standard normal distribution,
z=σx−μ.
a. z1=10168−164=0.40;P(X>168)=P(Z>0.40)==1−P(Z<0.40)==1−0.6554=0.3446=34.46% (from z-table).
b. z2=10150−164=−1.40;P(X<150)=P(Z<−1.40)==0.0808=8.08% (from z-table).
c. P(150<X<168)==P(−1.40<Z<0.40)==P(Z<0.40)−P(Z<−1.40)==0.6554−0.0808=0.5746=57.46%.
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