A group of students got the following scores in an achievement test: 9, 12 15, 18, 21 and 24. Consider samples of size 3 can be drawn from this population.
B. Construct the sampling distribution of the resulting sample means
The number of possible samples of size n=3 from a population of size N=6 is,
"=C_6^3= \\binom{6}{3}=20"
The sample means are derived from the formula, "\\bar x_i={\\sum x_i\\over3}"
The sampling distribution is as follows:
"\\begin{matrix}{\\bar x_i}&{12}&{13}&{14}&{15}&{16}&{17}&{18}&{19}&{20}&{21}\\\\{p(\\bar x_i)}&{\\frac{1}{{20}}}&{\\frac{1}{{20}}}&{\\frac{1}{{10}}}&{\\frac{3}{20}}&{\\frac{3}{{20}}}&{\\frac{3}{20}}&{\\frac{3}{{20}}}&{\\frac{1}{10}}&{\\frac{1}{{20}}}&{\\frac{1}{{20}}}\\end{matrix}"
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