If P(B) = 0.15, P(A | B) = 0.50, P(B′) = 0.85, and P(A | B′) = 0.60, find P(B | A)
"P(B|A) =\\cfrac{P(B)\\cdot P(A|B) } {P(B)\\cdot P(A|B)+P( B')\\cdot P(A|B')} =\\\\\n=\\cfrac{0.15\\cdot0.50} {0.15\\cdot0.50+0.85\\cdot0.60} =\\\\0.1282."
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