Question #330100

1.     A particular brand of petrol was used in 80 randomly chosen cars of the same model and age. The petrol consumption, x miles per gallon, was obtained for each car. The results are summarized by

∑x=1896 and ∑x2=45959.

Calculate a 99% confidence interval for the mean petrol consumption of all cars of this model and age.

 


1
Expert's answer
2022-04-21T04:15:11-0400

Since the population value of σ is unknown, we'll use the confidence interval for σ unknown.

Thus the 1 − α confidence interval is

xˉtα/2sn<μ<xˉ+tα/2sn\bar{x}-t_{\alpha/2}\cfrac{s}{\sqrt{n}}<\mu<\bar{x}+t_{\alpha/2}\cfrac{s}{\sqrt{n}}

where tα/2t_{\alpha/2} is the value from the t-distribution table for

P(T>tα/2)=α/2.P(T>t_{\alpha/2})=\alpha/2.

For a 99% confidence interval we have α = 0.01 and α/2 = 0.005.

Using the table for df = n - 1 = 80 - 1 = 79 (degrees of freedom, n = 80 - the sample size):

t0.005;79=2.639.t_{0.005;79}=2.639.

The sample mean:

xˉ=xn=189680=23.7.\bar{x}=\cfrac{\sum x}{n}=\cfrac{1896}{80}=23.7.

The sample variance:

s2=x2(x)2nn1==459591896280801=12.96.s^2=\cfrac{\sum x^2-\cfrac{(\sum x)^2}{n}}{n-1}=\\ =\cfrac{45959-\cfrac{1896^2}{80}}{80-1}=12.96.

The sample standard deviation:

s=12.96=3.60.s=\sqrt{12.96}=3.60.

Thus the 99% CI is

23.72.6393.6080<μ<23.7+2.6393.608022.64<μ<24.76.23.7-2.639\cdot\cfrac{3.60}{\sqrt{80}}<\mu<23.7+2.639\cdot\cfrac{3.60}{\sqrt{80}}\\ 22.64<\mu<24.76.





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