Question #330031

an electrical company claims that an average life of bulbs it manufactures is 1200 hours with standard deviation of 250 hours.If a random sample of 100 bulbs is chosen, what is the probability of the sample mean will be:




a.Greater than 1150 hours?



b.Less than 1250 hours?



c.Between 1150 and 1250 hours?​

1
Expert's answer
2022-04-18T17:00:37-0400

μ=1200σ=250n=100\mu=1200 \\ \sigma = 250 \\ n=100

a.

P(xˉ>1150)=1P(xˉ<1150)=1P(Z<11501200250/100)=1P(Z<2)=10.0227=0.9773P(\bar{x} > 1150) = 1 -P(\bar{x} < 1150) \\ = 1 -P(Z< \frac{1150-1200}{250 / \sqrt{100}} )\\ = 1 -P(Z< -2) \\ = 1 -0.0227 \\ = 0.9773

b.

P(xˉ<1250)=P(Z<12501200250/100)=P(Z<2)=0.9772P(\bar{x} < 1250) = P(Z < \frac{1250-1200}{250 / \sqrt{100}}) \\ = P(Z< 2) \\ = 0.9772

c.

P(1150<xˉ<1250)=P(xˉ<1250)P(xˉ<1150)=P(Z<12501200250/100)P(Z<11501200250/100)=P(Z<2)P(Z<2)=0.97720.0227=0.9545P(1150 < \bar{x} < 1250) = P(\bar{x} < 1250) -P(\bar{x} < 1150) \\ = P(Z < \frac{1250-1200}{250 / \sqrt{100}}) -P(Z < \frac{1150-1200}{250 / \sqrt{100}}) \\ = P(Z< 2) -P(Z< -2) \\ = 0.9772 -0.0227 \\ = 0.9545

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