Question #329957

A diagnostic test has a probability 0.95 of giving a positive result when applied to a person suffering from a certain disease, and a probability0.10 of giving a (false) positive when applied to a non- sufferer. It is estimated that 0.5 % of the population are sufferers. Suppose that the test is now administered to a person about whom we have no relevant information relating to the disease (apart from the fact that he/she comes from this population). Calculate the following probabilities:

(a) that the test result will be positive.

(b) that, given a positive result, the person is a sufferer.

(c) that, given a negative result, the person is a non-sufferer.


1
Expert's answer
2022-04-23T11:06:22-0400

Let A - the person is suffering from a disease,

B - the test is positive,

Then P(A)=0.005, P(BA)=0.95, P(B¬A)=0.1P(A)=0.005,~P(B|A)=0.95,~P(B|\lnot A)=0.1


a) We can split probability of event B into two parts: probability of B when A occurred + probability of B when A did not occur:

P(B)=P(BA)P(A)+P(B¬A)P(¬A)=0.950.005+0.10.995=0.1042510.4%P(B)=P(B|A)P(A)+P(B|\lnot A)P(\lnot A)=\\ 0.95\cdot0.005+0.1\cdot0.995=0.10425\approx10.4\%


b) According to the Bayes' theorem:

P(AB)=P(BA)P(A)P(B)==0.950.0050.104250.0456=4.56%P(A|B)=\frac{P(B|A)P(A)}{P(B)}=\\ =\frac{0.95\cdot0.005}{0.10425}\approx0.0456=4.56\%


c) According to the Bayes' theorem:

P(¬A¬B)=P(¬B¬A)P(¬A)P(¬B)P(\lnot A|\lnot B)=\frac{P(\lnot B|\lnot A)P(\lnot A)}{P(\lnot B)}

P(A)+P(¬A)=1,P(A)+P(\lnot A)=1, because events AA and ¬A\lnot A are complementary

Thus:

P(¬A)=1P(A)=10.005=0.995P(¬B)=1P(B)=10.10425=0.89575P(\lnot A)=1-P(A)=1-0.005=0.995\\ P(\lnot B)=1-P(B)=1-0.10425=0.89575

Given that the event ¬A\lnot A happened, events BB and ¬B\lnot B remain complementary:

P(B¬A)+P(¬B¬A)=1P(¬B¬A)=1P(B¬A)==10.1=0.9P(B|\lnot A)+P(\lnot B|\lnot A)=1\Rarr\\ \Rarr P(\lnot B|\lnot A)=1-P(B|\lnot A)=\\ =1-0.1=0.9

P(¬A¬B)=P(¬B¬A)P(¬A)P(¬B)==0.90.9950.895750.9997=99.97%P(\lnot A|\lnot B)=\frac{P(\lnot B|\lnot A)P(\lnot A)}{P(\lnot B)}=\\ =\frac{0.9\cdot0.995}{0.89575}\approx0.9997=99.97\%

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS