Suppose the mean amount of cholesterol in eggs labeled “large” is 186 milligrams, with standard deviation 7 milligrams. Find the probability that the mean amount of cholesterol in a sample of 144 eggs will be within 1.5 milligrams of the population mean.
We have a normal distribution, "\u03bc=186,\u03c3=7,n=144,"
"\\bar{x}_1=186-1.5=184.5,\\\\\n\\bar{x}_2=186+1.5=187.5."
Let's convert it to the standard normal distribution,
"\\bar{z}=\\cfrac{\\bar{x}-\\mu}{\\sigma\/\\sqrt{n}},\\\\\n\\bar{z}_1=\\cfrac{184.5-186}{7\/\\sqrt{144}}=-2.57,\\\\\n\\bar{z}_2=\\cfrac{187.5-186}{7\/\\sqrt{144}}=2.57,\\\\\nP(184.5<\\bar{X}<187.5)=P(-2.57<\\bar{Z}<2.57)=\\\\\n=P(\\bar{Z}<2.57)-P(\\bar{Z}<-2.57)=\\\\\n=0.9949-0.0051=0.9898\\text{ (from z-table).}"
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