A researcher of a cardboard manufacturing company would like to know the estimated thickness of the cardboard a machine produces How many cardboards should he measure if he wants to be 99% confident that the estimate is accurate to 1 mm. Study shows that the standard deviation is 3mm
The formula for error:
"E=z\\cdot \\cfrac{\\sigma}{\\sqrt{n}}."
Here
"E\\ -" the error, "E=1" mm;
"z\\ -" z-score, for 99% confidence level "z=2.576" ;
"\\sigma -" the he standard deviation, "\\sigma =" 3 mm;
"n\\ -" the sought sample size.
So,
"n=\\begin{pmatrix}\n \\cfrac{z\\cdot\\sigma}{E}\n\\end{pmatrix}^2=\\begin{pmatrix}\n \\cfrac{2.576\\cdot3}{1}\n\\end{pmatrix}^2=59.7."
The minimum amount of cardboards the researcher should measure is 60.
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